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Which of the following expressions will simulate a dice roll (in other words, the value stored in the variable dice will be either 1, 2, 3, 4, 5 or 6)? You can assume that the seed for the random number generator has already been set to the current time.

Alternatives

The contributor suggests B is the correct option
Option	Alternative	First answers	Confirmed answers
A	dice = (rand() % 5) + 1;	158 (23.72%)	1 (0.83%)
B	dice = (rand() % 6) + 1;	410 (61.56%)	120 (99.17%)
C	dice = (rand() % (6 - 1 + 1));	66 (9.91%)	0 (0.00%)
D	dice = (rand() % 1) + 6;	20 (3.00%)	0 (0.00%)
E	dice = (rand() % 10) - 4;	12 (1.80%)	0 (0.00%)

Explanation

The following explanation has been provided relating to this question:

The rand() function returns a random number, and computing modulo 6 will generate a value bewteen 0 and 5 inclusive.

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Comments

There are 3 comments for this question (1 top-level comment and 2 replies)

Written: 11:17pm, 26 Sep	Author has: 580 points and 9 badges

Hi, can someone please clarify what is rand ()? I know is it a random number but do you mean the number that is rolled by dice? Thanks.

	Written: 8:24am, 27 Sep	Author has: 644 points and 12 badges
	we haven't been taught rand yet, but the reason it's 6 is because the only possible reamainders of ANY number divided by 6 are 0,1,2,3,4,5. You can't have a remainder of 6 because remainder refers to the amound left over when it's divided by 6. It would go back to 0 in this case The perk of this is that no matter what the maximum rand number is (e.g. 2376287), we can get the number of possibilities we want. In this case, he means the number rolled by the dice, so we need to + 1 because we want the number to be from 1 to 6, not 0 to 5. I hope this helps!
	Written: 5:19pm, 28 Sep	Author has: 429 points and 5 badges
	the rand function produces a random number between 1 and RAND_MAX , I think its the max 32 bit integer value something like 32000, mod-ing it with 6 will produce values that range from 0-5 so we add one one toresult to get the desired range.
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