#include <cstdio>
    int printf( const char *format, ... );

The printf() function prints output to stdout, according to format and other arguments passed to printf(). The string format consists of two types of items - characters that will be printed to the screen, and format commands that define how the other arguments to printf() are displayed. Basically, you specify a format string that has text in it, as well as “special” characters that map to the other arguments of printf(). For example, this code

     char name[20] = "Bob";
     int age = 21;
     printf( "Hello %s, you are %d years old\n", name, age );

displays the following output:

     Hello Bob, you are 21 years old

The %s means, “insert the first argument, a string, right here.” The %d indicates that the second argument (an integer) should be placed there. There are different %-codes for different variable types, as well as options to limit the length of the variables and whatnot.

%dsigned integers
%isigned integers
%escientific notation, with a lowercase “e”
%Escientific notation, with a uppercase “E”
%ffloating point
%guse %e or %f, whichever is shorter
%Guse %E or %f, whichever is shorter
%sa string of characters
%uunsigned integer
%xunsigned hexadecimal, with lowercase letters
%Xunsigned hexadecimal, with uppercase letters
%pa pointer
%nthe argument shall be a pointer to an integer into which is placed the number of characters written so far

An integer placed between a % sign and the format command acts as a minimum field width specifier, and pads the output with spaces or zeros to make it long enough. If you want to pad with zeros, place a zero before the minimum field width specifier:


You may also specify the minimum field width in an int variable if instead of a number you put the * sign:

     int width = 12;
     int age = 100;
     printf("%*d", width, age);

You can also include a precision modifier, in the form of a .N where N is some number, before the format command:


The precision modifier has different meanings depending on the format command being used:

As with field width specifier, you may use an int variable to specify the precision modifier by using the * sign:

     const char* msg = "Hello printf";
     int string_size = strlen (msg);
     printf("msg: %.*s", string_size, msg);

All of printf()'s output is right-justified, unless you place a minus sign right after the % sign. For example,


will display a floating point number with a minimum of 12 characters, 4 decimal places, and left justified.

You may modify the %d, %i, %o, %u, and %x type specifiers with the letter l and the letter h to specify long and short data types (e.g. %hd means a short integer).

The %e, %f, and %g type specifiers can have the letter l before them to indicate that a double follows. The %g, %f, and %e type specifiers can be preceded with the character '#' to ensure that the decimal point will be present, even if there are no decimal digits.

The use of the '#' character with the %x type specifier indicates that the hexidecimal number should be printed with the '0x' prefix.

The use of the '#' character with the %o type specifier indicates that the octal value should be displayed with a 0 prefix.

Inserting a plus sign '+' into the type specifier will force positive values to be preceded by a '+' sign. Putting a space character ' ' there will force positive values to be preceded by a single space character.

You can also include constant escape sequences in the output string. The return value of printf() is the number of characters printed, or a negative number if an error occurred.

Related Topics: fprintf, puts, scanf, sprintf